# Line slope calculator 4x+5y=24

**Straight line given by points A[1; 4] and B[6; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+4.8

**Canonical form of the line equation:**4x+5y-24 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -4t+4 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 6

**Y intercept:**y

_{0}= q = 4.8

**Distance line from the origin:**d

_{0}= 3.7482

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[3.5; 2]

**Perpendicular Bisector equation:**5x-4y-9.5 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (6; 0) ; |OB| = 6**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 75°57'50″ = 1.3258 rad**